add HDPE water pipeline and water booster pump

[doneachh]

Closes # (if applicable).

Changes proposed in this Pull Request

Adding costs for HDPE water pipelines and pumps -> needed for integration of desalination and water management in pypsa-earth

Checklist

• Code changes are sufficiently documented; i.e. new functions contain docstrings and further explanations may be given in doc.
• Data source for new technologies is clearly stated.
• Newly introduced dependencies are added to environment.yaml (if applicable).
• A note for the release notes doc/release_notes.rst of the upcoming release is included.
• I consent to the release of this PR's code under the GPLv3 license.

[doneachh]

Hi @euronion :)
are you able to review this. I would need it for this PR: pypsa-meets-earth/pypsa-earth#1858
Thanks a lot.

[euronion]

Yes, I'll review. Next time feel free to ping me with the PR as soon as you feel like it is ready for review. :)

[euronion]

Thanks for the contribution, see the comments below and let me know if you have any question!

[euronion]

• Please rename it to "water pipeline HDPE", i.e. that the name reflects broader category -> diameter -> material details. So some of the info that you put in the details should also go into the name

• Can you add the figure where you extracted the data from in the report? (Probably figure 4-7?) and the date when you accessed the publication.

• The currency year should be 2022 instead of 2023, can you confirm/check?

• Are there any insights about the technology year of this data, whether this is from 1981 (like the pump station data)? Else we can keep it as 2023

[euronion]

Similar points as for the technology above:

• rename to something like "water pipeline booster pump"
• Exact location where the info is taken from the publication (I couldn't locate the origin of the data from the pub)
• It seems like the publication uses a formula with a scaling exponent != 1, so if you make an assumption on the HP of the pump, add this assumptions and ideally also the calculation to the details.
• Check technology (1981?) and currency year (2022)

[Eddy-JV]

Hi @doneachh and @euronion . I was the one working on this for the PR. So the source of the costs come from the formula (17) in : https://hypat.de/hypat-wAssets/docs/new/publikationen/HYPAT_WP_Water-Supply-for-Electrolysis-Plants.pdf

And the original sourcce of the formula comes from this report: https://www.countyofmonterey.gov/home/showdocument?id=18882

Where the 15570 USD are from 1981. So I used this formula to convert this number with a constant inflation of 2%:

Pump investment in millions Eur

invest_pumping_station = pump_station_cost_kw(
    power_kw=power_kW,
    usd_to_eur=snakemake.params.costs["default_exchange_rate"],
    a=35768, # 15570 # 35768 with inflation 2% 1981 till 2023
    b=0.558,
)

And the pump_station_cost_kw function is:

def pump_station_cost_kw(power_kw, usd_to_eur, a=35768, b=0.558):

Calculate pump station investment cost from installed power in kW.

Parameters:
-----------
power_kw : float or array
    Installed pump power in kW.
a : float
    Cost factor in Eur/HP (default 35768). Source: Inflation a2023=15570(1.02)**42≈35,768 USD/HP in https://hypat.de/hypat-wAssets/docs/new/publikationen/HYPAT_WP_Water-Supply-for-Electrolysis-Plants.pdf).
b : float
    Scaling exponent (default 0.558) Source: 1+b = 1-0.442 in https://hypat.de/hypat-wAssets/docs/new/publikationen/HYPAT_WP_Water-Supply-for-Electrolysis-Plants.pdf).
usd_to_eur : float
    Conversion rate from USD to EUR .

Returns:
--------
cost_eur : float or array
    Pump station cost in million EUR.

# Convert kW to HP
power_hp = power_kw / 0.7457

# Cost formula in USD
cost_usd = a * (power_hp ** b)

# Convert to EUR
cost_eur = cost_usd * usd_to_eur

# Return cost in million EUR
return cost_eur / 1e6

So technology (1981) and currency year (2023)

[euronion]

see points above :)

[euronion]

Efficiency is not clear for this technology.

Minimum: Add to the details what the efficiency unit is
Ideally: Change the unit to something more clear, maybe m3 water per kWh or something?

[Eddy-JV]

Hi @euronion . The efficiency here is taken from the same source by multiplying the motor efficiency wiith the pump efficiency: 0.85 x 0.9=0.765

I guess we can consider the unit to be m3 water per kWh